When Carbon Monoxide Reacts With Hydrogen Gas, Methane And Water Vapor Are Formed According To The Following R?

Posted by admin on Feb 21st

When carbon monoxide reacts with hydrogen gas, methane and water vapor are formed according to the following reaction
CO(g) + 3H2(g) = CH4(g) + H2O(g)
Analysis at equilibrium shows that Keq = 0.555, the [CO] = 0.921 M, the [H2] = 1.21 M, and the [CH4] = 0.0391 M. Calculate the equilibrium concentration for the water vapor.

Filed Under: Water for Gas FAQ
Tagged: Carbon, Formed, Hydrogen, Methane, Monoxide, Reacts, Vapor, Water, When, With

One Response to “When Carbon Monoxide Reacts With Hydrogen Gas, Methane And Water Vapor Are Formed According To The Following R?”

Feb 21st at 1:10 pm By: Emma P

.555=[Ch4][h2o]/[CO] [h2]^3
.555=.0391*[h20]/.921* 1.21^3
.555*.921 *1.21^3/.0391=[h20]
i think thats how you solve it the K formula is reactants concentration over products concentration